January
14, 2002
Statistical Inference
II. Every Xi has the same
probability distribution.
Recall the following 2 theorems from the Probability and Statistics I
class:
Theorem. If X1,…,Xn
is a SRS from a normal distribution with mean m and standard deviation s, then ![]()
|
Theorem (The Central Limit Theorem, CLT) If X1,…,Xn
is a SRS from a distribution with mean m and standard deviation s, then, if n is
sufficiently large (n>30),
|
Exercise 1. The foot is a length measure that
was originally introduced as a length of an average human foot. Since the
length of a foot differs among people, Germans in sixteenth century calculated
the average length of a foot for sixteen men selected at random, and this
average became the standard for “the correct foot”. Length of a foot of a man
is a random variable with mean 262.5 mm and standard deviation 12 mm.
A. If
the length of a foot is assumed to have a normal distribution, what is the
probability distribution of the average foot length of 16 randomly selected
men? (hint: the average foot length of 16 men,
)
B. Find
the probability distribution that the average foot length of 100 randomly
selected men. Do we have to make an assumption about normality of the
population distribution, as in part A, to find the distribution?
C. Find
the probability that the average foot length of 100 randomly selected men
exceeds 264 mm.
Point
Estimation.
|
Distribution of the sample mean for n=20 and n=100 |
|
|
Distribution of the
sample mean, Xi~N(5,1), n=20, number of repetitions = 1,000 |
Distribution of the
sample mean, Xi~N(5,1), n=100, number of repetitions = 1,000 |
|
|
|
|
Distribution of estimators of the variance |
|
|
Distribution of the
sample variance, Xi~N(100,50), n=10, number of repetitions = 1,000; mean of
sample variances: 2504.052 |
Distribution of the
sample variance*(n-1)/n,, Xi~N(100,50), n=10, number of repetitions = 1,000; Mean of sample
variances: 2238.597 |
|
|
|
|
Distribution of estimators of the parameter q for the uniform [0, q] distribution. |
|
|
2*sample mean,
Xi~U(0,5), number of repetitions = 1,000; mean: 5.002624 |
((n+1)/n)*max(xi),
Xi~U(0,5), number of repetitions = 1,000; mean: 5.000522 |
|
|
|
